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What will be the output of the following code snippet?1234567891011121314151617#include <stdio.h> int main() { int x = 20; switch (x) { case 10: if (x == 10) printf("Ten "); case 20: if (x == 20) printf("Twenty "); case 30: printf("Thirty "); default: printf("Other "); } return 0; }

Question

What will be the output of the following code snippet?1234567891011121314151617#include <stdio.h> int main() { int x = 20; switch (x) { case 10: if (x == 10) printf("Ten "); case 20: if (x == 20) printf("Twenty "); case 30: printf("Thirty "); default: printf("Other "); } return 0; }

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Solution

The output of the code will be "Twenty Thirty Other ".

Here's the step by step explanation:

  1. The variable x is initialized with the value 20.

  2. The switch statement checks the value of x.

  3. Since x is 20, it matches with the case 20:. So, it enters this case.

  4. Inside case 20:, there is an if statement that checks if x is 20. Since x is indeed 20, it prints "Twenty ".

  5. After executing the code inside case 20:, it does not encounter a break statement. So, it continues to execute the code in the next case, which is case 30:. It prints "Thirty ".

  6. Again, it does not encounter a break statement, so it continues to execute the code in the default: case. It prints "Other ".

  7. The program ends with a return statement return 0;.

So, the final output is "Twenty Thirty Other ".

Note: The break statement is used to terminate the execution of the nearest enclosing loop or conditional statement in which it appears. Without a break statement, the program continues to execute the next case in the switch statement, even if the case does not match the switch expression.

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