The vertex form of a parabola's equation is given by x = a(y - k)² + h, where (h, k) is the vertex of the parabola.

In the given equation x = 8(y - 1)² - 15, a = 8, h = -15, and k = 1.

To convert this into the standard form, we expand the equation:

x = 8(y² - 2y + 1) - 15
x = 8y² - 16y + 8 - 15
x = 8y² - 16y - 7

So, the standard form of the equation is x = 8y² - 16y - 7.

Question

The vertex form of a parabola's equation is given by x = a(y - k)² + h, where (h, k) is the vertex of the parabola.

In the given equation x = 8(y - 1)² - 15, a = 8, h = -15, and k = 1.

To convert this into the standard form, we expand the equation:

x = 8(y² - 2y + 1) - 15
x = 8y² - 16y + 8 - 15
x = 8y² - 16y - 7

So, the standard form of the equation is x = 8y² - 16y - 7.

Knowee AI · Accepted Answer

The vertex form of a parabola's equation is given by x = a(y - k)² + h, where (h, k) is the vertex of the parabola.

In the given equation x = 8(y - 1)² - 15, a = 8, h = -15, and k = 1.

To convert this into the standard form, we expand the equation:

x = 8(y² - 2y + 1) - 15
x = 8y² - 16y + 8 - 15
x = 8y² - 16y - 7

So, the standard form of the equation is x = 8y² - 16y - 7.

The vertex form of the equation of a parabola is x = 8(y - 1)2 - 15.What is the standard form of the equation?