The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation y = (x - 4)^2 + 22, we can expand it to get the standard form.

First, expand (x - 4)^2. This is equivalent to (x - 4)(x - 4), which simplifies to x^2 - 8x + 16.

Then, add 22 to the result to get the standard form. So, x^2 - 8x + 16 + 22 simplifies to x^2 - 8x + 38.

Therefore, the standard form of the equation is y = x^2 - 8x + 38, which corresponds to option B.

Question

The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation y = (x - 4)^2 + 22, we can expand it to get the standard form.

First, expand (x - 4)^2. This is equivalent to (x - 4)(x - 4), which simplifies to x^2 - 8x + 16.

Then, add 22 to the result to get the standard form. So, x^2 - 8x + 16 + 22 simplifies to x^2 - 8x + 38.

Therefore, the standard form of the equation is y = x^2 - 8x + 38, which corresponds to option B.

Knowee AI · Accepted Answer

The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation y = (x - 4)^2 + 22, we can expand it to get the standard form.

First, expand (x - 4)^2. This is equivalent to (x - 4)(x - 4), which simplifies to x^2 - 8x + 16.

Then, add 22 to the result to get the standard form. So, x^2 - 8x + 16 + 22 simplifies to x^2 - 8x + 38.

Therefore, the standard form of the equation is y = x^2 - 8x + 38, which corresponds to option B.

The vertex form of the equation of a parabola is y = (x - 4)2 + 22.What is the standard form of the equation?A.y = x2 + x + 11B.y = x2 - 8x + 38C.y = 4x2 - 8x + 38D.y = x2 + 8x + 22