The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation y = (x - 3)^2 + 36, we can expand it to get the standard form.

First, expand (x - 3)^2. This is equivalent to (x - 3)(x - 3), which simplifies to x^2 - 6x + 9.

So, the equation becomes y = x^2 - 6x + 9 + 36.

Combine like terms to get the standard form: y = x^2 - 6x + 45.

So, the correct answer is C. y = x^2 - 6x + 45.

Question

The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation y = (x - 3)^2 + 36, we can expand it to get the standard form.

First, expand (x - 3)^2. This is equivalent to (x - 3)(x - 3), which simplifies to x^2 - 6x + 9.

So, the equation becomes y = x^2 - 6x + 9 + 36.

Combine like terms to get the standard form: y = x^2 - 6x + 45.

So, the correct answer is C. y = x^2 - 6x + 45.

Knowee AI · Accepted Answer

The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation y = (x - 3)^2 + 36, we can expand it to get the standard form.

First, expand (x - 3)^2. This is equivalent to (x - 3)(x - 3), which simplifies to x^2 - 6x + 9.

So, the equation becomes y = x^2 - 6x + 9 + 36.

Combine like terms to get the standard form: y = x^2 - 6x + 45.

So, the correct answer is C. y = x^2 - 6x + 45.

The vertex form of the equation of a parabola is y = (x - 3)2 + 36.What is the standard form of the equation?A.y = x2 + 6x + 36B.y = 3x2 - 6x + 45C.y = x2 - 6x + 45D.y = x2 + x + 18SUBMITarrow_backPREVIOUS