The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation of a parabola y = (x - 4)^2 + 22, we can expand this to get to the standard form.

First, expand (x - 4)^2. This is equivalent to (x - 4)(x - 4), which simplifies to x^2 - 8x + 16.

So, y = x^2 - 8x + 16 + 22.

Combine like terms to get the standard form: y = x^2 - 8x + 38.

So, the standard form of the equation is y = x^2 - 8x + 38, which corresponds to option C.

Question

The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation of a parabola y = (x - 4)^2 + 22, we can expand this to get to the standard form.

First, expand (x - 4)^2. This is equivalent to (x - 4)(x - 4), which simplifies to x^2 - 8x + 16.

So, y = x^2 - 8x + 16 + 22.

Combine like terms to get the standard form: y = x^2 - 8x + 38.

So, the standard form of the equation is y = x^2 - 8x + 38, which corresponds to option C.

Knowee AI · Accepted Answer

The standard form of a quadratic equation is y = ax^2 + bx + c.

Given the vertex form of the equation of a parabola y = (x - 4)^2 + 22, we can expand this to get to the standard form.

First, expand (x - 4)^2. This is equivalent to (x - 4)(x - 4), which simplifies to x^2 - 8x + 16.

So, y = x^2 - 8x + 16 + 22.

Combine like terms to get the standard form: y = x^2 - 8x + 38.

So, the standard form of the equation is y = x^2 - 8x + 38, which corresponds to option C.

The vertex form of the equation of a parabola is y = (x - 4)2 + 22.What is the standard form of the equation?A.y = x2 + x + 11B.y = 4x2 - 8x + 38C.y = x2 - 8x + 38D.y = x2 + 8x + 22SUBMITarrow_backPREVIOUS