The vertex form of the equation of a parabola is y = 4(x - 2)2 - 1.What is the standard form of the equation?A.y = 4x2 - 16x + 2B.y = 4x2 - 16x + 15C.y = 4x2 - 3D.y = 16x2 - 5SUBMITarrow_backPREVIOUS
Question
The vertex form of the equation of a parabola is y = 4(x - 2)2 - 1.What is the standard form of the equation?A.y = 4x2 - 16x + 2B.y = 4x2 - 16x + 15C.y = 4x2 - 3D.y = 16x2 - 5SUBMITarrow_backPREVIOUS
Solution
The standard form of a quadratic equation is y = ax^2 + bx + c.
To convert the vertex form y = 4(x - 2)^2 - 1 to the standard form, you need to expand the equation.
First, square the binomial (x - 2)^2 to get x^2 - 4x + 4.
Then, multiply the result by 4 to get 4x^2 - 16x + 16.
Finally, subtract 1 from the result to get 4x^2 - 16x + 15.
So, the standard form of the equation is y = 4x^2 - 16x + 15.
Therefore, the correct answer is B. y = 4x^2 - 16x + 15.
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