The vertex form of a parabola's equation is given by x = a(y - h)² + k, where (h, k) is the vertex of the parabola.

In the given equation x = (y - 2)² + 36, we can see that a = 1, h = 2, and k = 36.

To convert this into the standard form, we expand the square term:

x = (y - 2)² + 36
x = (y² - 4y + 4) + 36
x = y² - 4y + 40

So, the standard form of the equation is x = y² - 4y + 40, which corresponds to option C.

Question

The vertex form of a parabola's equation is given by x = a(y - h)² + k, where (h, k) is the vertex of the parabola.

In the given equation x = (y - 2)² + 36, we can see that a = 1, h = 2, and k = 36.

To convert this into the standard form, we expand the square term:

x = (y - 2)² + 36
x = (y² - 4y + 4) + 36
x = y² - 4y + 40

So, the standard form of the equation is x = y² - 4y + 40, which corresponds to option C.

Knowee AI · Accepted Answer

The vertex form of a parabola's equation is given by x = a(y - h)² + k, where (h, k) is the vertex of the parabola.

In the given equation x = (y - 2)² + 36, we can see that a = 1, h = 2, and k = 36.

To convert this into the standard form, we expand the square term:

x = (y - 2)² + 36
x = (y² - 4y + 4) + 36
x = y² - 4y + 40

So, the standard form of the equation is x = y² - 4y + 40, which corresponds to option C.

The vertex form of the equation of a parabola is x = (y - 2)2 + 36.What is the standard form of the equation?A.x = y2 + y + 12B.x = 2y2 - 4y + 40C.x = y2 - 4y + 40D.x = y2 + 4y + 36SUBMITarrow_backPREVIOUS