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A sample containing 0.010 mol of anhydrous calcium nitrate is heated strongly until it fullydecomposes.All the gas produced is collected and its volume measured at room conditions.What is the volume of gas produced?

Question

A sample containing 0.010 mol of anhydrous calcium nitrate is heated strongly until it fullydecomposes.All the gas produced is collected and its volume measured at room conditions.What is the volume of gas produced?

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Solution

The decomposition of calcium nitrate can be represented by the following balanced chemical equation:

2Ca(NO3)2(s) → 2CaO(s) + 4NO2(g) + O2(g)

From the stoichiometry of the reaction, 2 moles of calcium nitrate produce 4 moles of nitrogen dioxide and 1 mole of oxygen, a total of 5 moles of gas.

Therefore, 0.010 moles of calcium nitrate will produce 0.010 * 5/2 = 0.025 moles of gas.

At room temperature and pressure (RTP), 1 mole of any gas occupies 24.0 dm^3.

Therefore, the volume of gas produced is 0.025 * 24.0 = 0.6 dm^3.

This problem has been solved

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