This problem can be solved using the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas and the temperature, and inversely proportional to the pressure. However, since the pressure and temperature are constant in this problem, we can simplify this to a direct proportion between volume and number of moles.

The initial condition is 1.70 moles occupying 3800 mL (or 3.8 L). We can set up the proportion as follows:

1.70 moles / 3.8 L = 2.60 moles / x L

Solving for x gives us the new volume:

x = 2.60 moles * 3.8 L / 1.70 moles = 5.82 L

So, the new volume of the gas is approximately 5.82 L. The closest answer to this is C. 5.81 L.

Question

This problem can be solved using the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas and the temperature, and inversely proportional to the pressure. However, since the pressure and temperature are constant in this problem, we can simplify this to a direct proportion between volume and number of moles.

The initial condition is 1.70 moles occupying 3800 mL (or 3.8 L). We can set up the proportion as follows:

1.70 moles / 3.8 L = 2.60 moles / x L

Solving for x gives us the new volume:

x = 2.60 moles * 3.8 L / 1.70 moles = 5.82 L

So, the new volume of the gas is approximately 5.82 L. The closest answer to this is C. 5.81 L.

Knowee AI · Accepted Answer

This problem can be solved using the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas and the temperature, and inversely proportional to the pressure. However, since the pressure and temperature are constant in this problem, we can simplify this to a direct proportion between volume and number of moles.

The initial condition is 1.70 moles occupying 3800 mL (or 3.8 L). We can set up the proportion as follows:

1.70 moles / 3.8 L = 2.60 moles / x L

Solving for x gives us the new volume:

x = 2.60 moles * 3.8 L / 1.70 moles = 5.82 L

So, the new volume of the gas is approximately 5.82 L. The closest answer to this is C. 5.81 L.

A sample of Nitrogen gas has 1.70 mols and occupies 3800mL at 25C. What volume will it occupy if it now has 2.60mols?A.5811.76 LB. 1.16 LC. 5.81 LD. 2.48 L

Question

Solution

Similar Questions

Upgrade your grade with Knowee