What is the volume of 0.789 moles of gas that exerts 1.15 atm of pressure at 376 K? Question 7Select one:a.4250 Lb.0.0294 Lc.36.5 Ld.21.2 L
Question
What is the volume of 0.789 moles of gas that exerts 1.15 atm of pressure at 376 K? Question 7Select one:a.4250 Lb.0.0294 Lc.36.5 Ld.21.2 L
Solution
To solve this problem, we can use the ideal gas law equation, which is PV = nRT.
Where: P = pressure V = volume n = number of moles R = ideal gas constant T = temperature
Given: P = 1.15 atm n = 0.789 moles T = 376 K R = 0.0821 L.atm/(mol.K) (This is the value of R in these units)
We need to solve for V (volume).
Rearranging the equation to solve for V gives us V = nRT/P.
Substituting the given values into the equation gives us V = (0.789 moles * 0.0821 L.atm/(mol.K) * 376 K) / 1.15 atm.
Calculating this gives us V ≈ 21.2 L.
So, the correct answer is d. 21.2 L.
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