31. A container holds 60.0 mL of nitrogen at 30.0 degrees Celsius. What will be its volume if the temperature increases to 65.0 degrees Celsius?

To solve this problem, we can use the formula for Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas are kept constant. The formula is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Step 1: Convert the temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = C + 273.15.

T1 = 30.0 degrees Celsius = 30.0 + 273.15 = 303.15 K T2 = 65.0 degrees Celsius = 65.0 + 273.15 = 338.15 K

Step 2: Substitute the known values into the formula and solve for V2.

V1/T1 = V2/T2 60.0 mL / 303.15 K = V2 / 338.15 K V2 = (60.0 mL / 303.15 K) * 338.15 K V2 = 67.0 mL

So, if the temperature of the nitrogen increases to 65.0 degrees Celsius, its volume will increase to approximately 67.0 mL.