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Complete the square to re-write the quadratic function in vertex form:y, equals, x, squared, minus, 4, x, plus, 6y=x 2 −4x+6

Question

Complete the square to re-write the quadratic function in vertex form:y, equals, x, squared, minus, 4, x, plus, 6y=x 2 −4x+6

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Solution

Sure, let's complete the square to rewrite the quadratic function in vertex form.

Given the quadratic function: y=x24x+6 y = x^2 - 4x + 6

Step 1: Start with the quadratic and linear terms. y=x24x y = x^2 - 4x

Step 2: To complete the square, take the coefficient of x x , which is 4-4, divide it by 2, and then square it. (42)2=(2)2=4 \left(\frac{-4}{2}\right)^2 = (-2)^2 = 4

Step 3: Add and subtract this square inside the equation. y=x24x+44+6 y = x^2 - 4x + 4 - 4 + 6

Step 4: Group the perfect square trinomial and the constants. y=(x24x+4)+(4+6) y = (x^2 - 4x + 4) + (-4 + 6)

Step 5: Rewrite the perfect square trinomial as a binomial squared. y=(x2)2+2 y = (x - 2)^2 + 2

So, the quadratic function in vertex form is: y=(x2)2+2 y = (x - 2)^2 + 2

This problem has been solved

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