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Complete the square to re-write the quadratic function in vertex form:y, equals, x, squared, plus, 4, x, plus, 4y=x 2 +4x+4AnswerAttempt 1 out of 2

Question

Complete the square to re-write the quadratic function in vertex form:y, equals, x, squared, plus, 4, x, plus, 4y=x 2 +4x+4AnswerAttempt 1 out of 2

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Solution

Sure, let's complete the square to rewrite the quadratic function in vertex form.

Given the quadratic function: y=x2+4x+4 y = x^2 + 4x + 4

Step 1: Identify the coefficient of the x x term, which is 4.

Step 2: Take half of this coefficient and square it. (42)2=22=4 \left(\frac{4}{2}\right)^2 = 2^2 = 4

Step 3: Rewrite the quadratic function by adding and subtracting this squared value inside the equation. y=x2+4x+4 y = x^2 + 4x + 4 y=(x2+4x+4) y = (x^2 + 4x + 4)

Step 4: Notice that x2+4x+4 x^2 + 4x + 4 is a perfect square trinomial. It can be factored as: y=(x+2)2 y = (x + 2)^2

So, the quadratic function in vertex form is: y=(x+2)2 y = (x + 2)^2

The vertex form of the given quadratic function is: y=(x+2)2 y = (x + 2)^2

This problem has been solved

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