To solve this problem, we can use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas if the temperature and pressure are held constant. This can be expressed as V1/n1 = V2/n2, where V1 and n1 are the initial volume and number of moles, and V2 and n2 are the final volume and number of moles.

Step 1: Identify the initial volume (V1) and number of moles (n1). In this case, V1 = 10 L and n1 = 0.568 moles.

Step 2: Identify the final number of moles (n2). In this case, n2 = 0.450 moles.

Step 3: Substitute the known values into the equation and solve for the final volume (V2).

V1/n1 = V2/n2
10 L / 0.568 moles = V2 / 0.450 moles

Solving for V2 gives:

V2 = (10 L / 0.568 moles) * 0.450 moles = 7.92 L

So, the new volume of the container will be approximately 7.92 L.

Question

To solve this problem, we can use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas if the temperature and pressure are held constant. This can be expressed as V1/n1 = V2/n2, where V1 and n1 are the initial volume and number of moles, and V2 and n2 are the final volume and number of moles.

Step 1: Identify the initial volume (V1) and number of moles (n1). In this case, V1 = 10 L and n1 = 0.568 moles.

Step 2: Identify the final number of moles (n2). In this case, n2 = 0.450 moles.

Step 3: Substitute the known values into the equation and solve for the final volume (V2).

V1/n1 = V2/n2
10 L / 0.568 moles = V2 / 0.450 moles

Solving for V2 gives:

V2 = (10 L / 0.568 moles) * 0.450 moles = 7.92 L

So, the new volume of the container will be approximately 7.92 L.

Knowee AI · Accepted Answer

To solve this problem, we can use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas if the temperature and pressure are held constant. This can be expressed as V1/n1 = V2/n2, where V1 and n1 are the initial volume and number of moles, and V2 and n2 are the final volume and number of moles.

Step 1: Identify the initial volume (V1) and number of moles (n1). In this case, V1 = 10 L and n1 = 0.568 moles.

Step 2: Identify the final number of moles (n2). In this case, n2 = 0.450 moles.

Step 3: Substitute the known values into the equation and solve for the final volume (V2).

V1/n1 = V2/n2
10 L / 0.568 moles = V2 / 0.450 moles

Solving for V2 gives:

V2 = (10 L / 0.568 moles) * 0.450 moles = 7.92 L

So, the new volume of the container will be approximately 7.92 L.

An oxygen gas has volume of 10 L and contains .568 moles. What will be the new volume of the container if .450 moles will be used to fill in the adjustable container?

Question

Solution

Similar Questions

Upgrade your grade with Knowee