Complete the code segment to check whether the number is an Armstrong number or not.Armstrong Number:
Question
Complete the code segment to check whether the number is an Armstrong number or not.Armstrong Number:
Solution
Sure, here is a Python code snippet that checks if a number is an Armstrong number or not:
def is_armstrong(n):
# Convert integer to string to calculate the length (number of digits)
num_str = str(n)
num_len = len(num_str)
# Calculate the sum of the power of each digit
sum = 0
for digit in num_str:
sum += int(digit) ** num_len
# Check if sum is equal to the original number
if sum == n:
return True
else:
return False
# Test the function
num = int(input("Enter a number: "))
if is_armstrong(num):
print(num, "is an Armstrong number")
else:
print(num, "is not an Armstrong number")
This code defines a function is_armstrong(n) that checks if a number n is an Armstrong
Similar Questions
Write a C program to check whether a number is Armstrong number or not.
You are given an integer 'n'. Return 'true' if 'n' is an Armstrong number, and 'false' otherwise.An Armstrong number is a number (with 'k' digits) such that the sum of its digits raised to 'kth' power is equal to the number itself. For example, 371 is an Armstrong number because 3^3 + 7^3 + 1^3 = 371.
Write a C program to determine if a given integer is an Armstrong number or not. An Armstrong number (also known as a narcissistic number or pluperfect digital invariant) is a number that is equal to the sum of its own digits raised to the power of the number of digits. For example, 153 is an Armstrong number because 13+53+33=15313+53+33=153.Design a function called isArmstrong that takes an integer num as input and returns 1 if num is an Armstrong number, and 0 otherwise. Your program should prompt the user to enter an integer, call the isArmstrong function to check if it is an Armstrong number, and display an appropriate message indicating whether the entered number is an Armstrong number or not.inputEnter a number: 153output153 is an Armstrong number.
Write the C code to Check whether a given 4 digit number is an Armstrong number or not. The formula to be used here. if 1234 is the input then armstrong number is(1^4+2^4+3^4+4^4)Sample Input:n=1532Output:Not ArmstrongSample Input:n=1634Output:Armstrong
#include<math.h> int checkArmstrongNumber(int n) { int originalNumber, remainder, result = 0, count = 0; originalNumber = n; // To get the number of digits while (originalNumber != 0) { originalNumber /= 10; ++count; } originalNumber = n; // Check if the number is an Armstrong number while (originalNumber != 0) { remainder = originalNumber % 10; result += pow(remainder, count); originalNumber /= 10; } if (result == n) return 1; else return result; } Input Your Output Expected Output 371 970554640 1
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