Sure, here is a step-by-step solution in Python:

1. First, we need to convert the integer 'n' to a string to easily access each digit. We can do this with the str() function:

```python
n_str = str(n)
```

2. Next, we calculate the number of digits 'k' in 'n'. This can be done by using the len() function:

```python
k = len(n_str)
```

3. Now, we initialize a variable to hold the sum of each digit raised to the 'kth' power:

```python
sum = 0
```

4. Then, we iterate over each digit in 'n_str', convert it back to an integer, raise it to the 'kth' power, and add it to 'sum':

```python
for digit in n_str:
sum += int(digit) ** k
```

5. Finally, we return 'true' if 'sum' is equal to 'n', and 'false' otherwise:

```python
return sum == n
```

So, the complete Python function would look like this:

```python
def is_armstrong(n):
n_str = str(n)
k = len(n_str)
sum = 0
for digit in n_str:
sum += int(digit) ** k
return sum == n
```

Question

Sure, here is a step-by-step solution in Python:

1. First, we need to convert the integer 'n' to a string to easily access each digit. We can do this with the str() function:

```python
n_str = str(n)
```

2. Next, we calculate the number of digits 'k' in 'n'. This can be done by using the len() function:

```python
k = len(n_str)
```

3. Now, we initialize a variable to hold the sum of each digit raised to the 'kth' power:

```python
sum = 0
```

4. Then, we iterate over each digit in 'n_str', convert it back to an integer, raise it to the 'kth' power, and add it to 'sum':

```python
for digit in n_str:
    sum += int(digit) ** k
```

5. Finally, we return 'true' if 'sum' is equal to 'n', and 'false' otherwise:

```python
return sum == n
```

So, the complete Python function would look like this:

```python
def is_armstrong(n):
    n_str = str(n)
    k = len(n_str)
    sum = 0
    for digit in n_str:
        sum += int(digit) ** k
    return sum == n
```

Knowee AI · Accepted Answer