Sure! Here is a step-by-step guide to write a program in C to check whether a number is an Armstrong number or not:

Step 1: Include the necessary header files.

#include <stdio.h> #include <math.h>

Step 2: Define the main function.

int main() { // Your code goes here return 0; }

Step 3: Declare the necessary variables.

int number, originalNumber, remainder, result = 0, n = 0;

Step 4: Take input from the user.

printf("Enter an integer: "); scanf("%d", &number);

Step 5: Store the original number in a separate variable.

originalNumber = number;

Step 6: Calculate the number of digits in the given number.

while (originalNumber != 0) { originalNumber /= 10; ++n; }

Step 7: Calculate the Armstrong number.

originalNumber = number; while (originalNumber != 0) { remainder = originalNumber % 10; result += pow(remainder, n); originalNumber /= 10; }

Step 8: Check if the calculated result is equal to the original number.

if (result == number) printf("%d is an Armstrong number.", number); else printf("%d is not an Armstrong number.", number);

Step 9: End the program.

return 0;

That's it! You have successfully written a C program to check whether a number is an Armstrong number or not.

This problem has been solved

Question

Sure! Here is a step-by-step guide to write a program in C to check whether a number is an Armstrong number or not:

Step 1: Include the necessary header files.

#include <stdio.h>
#include <math.h>

Step 2: Define the main function.

int main() {
    // Your code goes here
    return 0;
}

Step 3: Declare the necessary variables.

int number, originalNumber, remainder, result = 0, n = 0;

Step 4: Take input from the user.

printf("Enter an integer: ");
scanf("%d", &number);

Step 5: Store the original number in a separate variable.

originalNumber = number;

Step 6: Calculate the number of digits in the given number.

while (originalNumber != 0) {
    originalNumber /= 10;
    ++n;
}

Step 7: Calculate the Armstrong number.

originalNumber = number;

while (originalNumber != 0) {
    remainder = originalNumber % 10;
    result += pow(remainder, n);
    originalNumber /= 10;
}

Step 8: Check if the calculated result is equal to the original number.

if (result == number)
    printf("%d is an Armstrong number.", number);
else
    printf("%d is not an Armstrong number.", number);

Step 9: End the program.

return 0;

That's it! You have successfully written a C program to check whether a number is an Armstrong number or not.

This problem has been solved

Knowee AI · Accepted Answer