A 528. mL solution was made by mixing 91.7 mL of ethanol, which has a density of 0.79 /gmL, and 431. mL of water, which has a density of 1.0 /gmL.Calculate the volume percent of ethanol in this solution.Be sure your answer has the right number of significant digits.
Question
A 528. mL solution was made by mixing 91.7 mL of ethanol, which has a density of 0.79 /gmL, and 431. mL of water, which has a density of 1.0 /gmL.Calculate the volume percent of ethanol in this solution.Be sure your answer has the right number of significant digits.
Solution
To calculate the volume percent of ethanol in the solution, we need to follow these steps:
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First, we need to find the total volume of the solution. This is given by the sum of the volume of ethanol and the volume of water. So, the total volume is 91.7 mL (ethanol) + 431 mL (water) = 522.7 mL.
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Next, we calculate the volume percent of ethanol. This is given by the volume of ethanol divided by the total volume of the solution, multiplied by 100. So, the volume percent of ethanol is (91.7 mL / 522.7 mL) * 100 = 17.5%.
Therefore, the volume percent of ethanol in the solution is 17.5%. This answer has the right number of significant digits.
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