A 371. mL solution was made by mixing 42.8 mL of methanol, which has a density of 0.79 /gmL, and 311. mL of water, which has a density of 1.0 /gmL.Calculate the volume percent of methanol in this solution.Be sure your answer has the right number of significant digits.
Question
A 371. mL solution was made by mixing 42.8 mL of methanol, which has a density of 0.79 /gmL, and 311. mL of water, which has a density of 1.0 /gmL.Calculate the volume percent of methanol in this solution.Be sure your answer has the right number of significant digits.
Solution
To calculate the volume percent of methanol in the solution, we need to follow these steps:
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First, we need to find the total volume of the solution. This is given by the sum of the volume of methanol and the volume of water. So, the total volume is 42.8 mL (methanol) + 311 mL (water) = 353.8 mL.
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Next, we calculate the volume percent of methanol. This is given by the volume of methanol divided by the total volume of the solution, multiplied by 100%. So, the volume percent of methanol is (42.8 mL / 353.8 mL) * 100% = 12.1%.
Therefore, the volume percent of methanol in the solution is 12.1%.
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