What is the mass percent of ethyl alcohol in a solution containing 62 mL of ethyl alcohol mixed into 200 mL of water? (Note: Density of ethyl alcohol = 0.8 g/mL; density of water = 1 g/mL.)
Question
What is the mass percent of ethyl alcohol in a solution containing 62 mL of ethyl alcohol mixed into 200 mL of water? (Note: Density of ethyl alcohol = 0.8 g/mL; density of water = 1 g/mL.)
Solution
Step 1: Calculate the mass of each component.
The mass of ethyl alcohol is given by the volume multiplied by its density. So, 62 mL * 0.8 g/mL = 49.6 g.
The mass of water is given by the volume multiplied by its density. So, 200 mL * 1 g/mL = 200 g.
Step 2: Calculate the total mass of the solution.
The total mass of the solution is the sum of the mass of the ethyl alcohol and the mass of the water. So, 49.6 g + 200 g = 249.6 g.
Step 3: Calculate the mass percent of ethyl alcohol.
The mass percent of ethyl alcohol is given by the mass of the ethyl alcohol divided by the total mass of the solution, multiplied by 100%. So, (49.6 g / 249.6 g) * 100% = 19.87%.
Therefore, the mass percent of ethyl alcohol in the solution is approximately 19.87%.
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