Sam and David are trying out a new wall at the rock-climbing gym. Sam starts up the wall first. After he is 5 feet in the air, David starts climbing up the wall next to Sam. They climb at the same speed up the wall. Let d be David's height up the wall, in feet, and let s be Sam's height up the wall, in feet.The equation s=d+5 represents this situation. Graph the equation.1234567891012345678910dsDavid's height, in feetSam's height, in feetSubmit

Billy and his younger brother, Reggie, are going to race each other to the park. They will start running at the same time, but Billy is letting Reggie start 20 meters ahead. Billy can run 8 meters per second, and Reggie can run 6 meters per second.Which equation can you use to find s, the number of seconds it will take for Billy to catch up to Reggie if they each run as fast as they can?20+6s=8s20s+6=8sHow long will it take for Billy to catch up to Reggie?Simplify any fractions. seconds

A monkey is climbing a tree. For the first second and all the consecutive odd seconds, the monkey goes up by a𝑎 meters and for every consecutive even second after the first, the monkey comes down by b𝑏 meters.Find the height the monkey reaches after n𝑛 seconds.InputThe first line has two integers a𝑎 and b𝑏 (0≤b≤a≤0≤𝑏≤𝑎≤ 104104)The second line has a single integer n𝑛 (00 ≤n≤≤𝑛≤ 105105)OutputPrint a single integer, the height reached by the monkey after n𝑛 secondsExampleinputCopy5 34outputCopy4NoteThe monkey moves 55 meters up in the 1st1𝑠𝑡 and 3rd3𝑟𝑑 second and 33 meters down in the 2nd2𝑛𝑑 and 4th4𝑡ℎ second, thus the monkey reaches 5+5−3−3=45+5−3−3=4 meters after 44 seconds.

A stone was dropped off a cliff and hit the ground with a speed of 152 ft/s. What is the height of the cliff? (Use 32 ft/s2 for the acceleration due to gravity.)Part 1 of 4We know that s(t) = 12at2 + v0t + s0. In this situation, we have a = ft/s2, v0 = ft/s, and s0 = h, where h is the height of the cliff (in feet) that we wish to find.

We know that s(t) = 12at2 + v0t + s0. In this situation, we have a = ft/s2, v0 = ft/s, and s0 = h, where h is the height of the cliff (in feet) that we wish to find.

A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the distance travelled in m.