A stone was dropped off a cliff and hit the ground with a speed of 152 ft/s. What is the height of the cliff? (Use 32 ft/s2 for the acceleration due to gravity.)Part 1 of 4We know that s(t) = 12at2 + v0t + s0. In this situation, we have a = ft/s2, v0 = ft/s, and s0 = h, where h is the height of the cliff (in feet) that we wish to find.

We know that s(t) = 12at2 + v0t + s0. In this situation, we have a = ft/s2, v0 = ft/s, and s0 = h, where h is the height of the cliff (in feet) that we wish to find.

When the stone hits the ground, its height is 0 ft. We can now use0 = s(4.75) = −16 2  + h.Solving for h we find that the height of the cliff ish = ft.

A rocket, initially at rest, is fired horizontally with a horizontal acceleration of 12 m/s2. If the rocket is fired from a cliff 80 meters high, what is the distance in meters between the landing location and the bottom of the cliff? (Note: use g=10 m/s2).

A hiker throws a stone from the upper edge of a vertical cliff. The stone's initial velocity is 25.0 m/s directed at 40.0° with the face of the cliff, as shown in the figure.The stone hits the ground 3.75 s after being thrown.How far from the foot of the cliff does the stone land?Ignore air friction and express your answer in meters.

A stone thrown vertically upward at12m/s. How high would the stone be when its speed is 8m/s?a.4.1mb.4.5mc.4.8md.4.9m