We know that s(t) = 12at2 + v0t + s0. In this situation, we have a = ft/s2, v0 = ft/s, and s0 = h, where h is the height of the cliff (in feet) that we wish to find.
Question
We know that s(t) = 12at2 + v0t + s0. In this situation, we have a = ft/s2, v0 = ft/s, and s0 = h, where h is the height of the cliff (in feet) that we wish to find.
Solution
It seems like you haven't provided a specific question to answer. The information you've given relates to the equation of motion s(t) = 12at^2 + v0t + s0, where 's' is the displacement, 'a' is the acceleration, 'v0' is the initial velocity, 't' is the time, and 's0' is the initial displacement or position. In this case, 'a' is given in feet per second squared (ft/s^2), 'v0' is in feet per second (ft/s), and 's0' is the height of the cliff 'h'. If you provide a specific question related to this information, I'd be happy to help answer it.
Similar Questions
A stone was dropped off a cliff and hit the ground with a speed of 152 ft/s. What is the height of the cliff? (Use 32 ft/s2 for the acceleration due to gravity.)Part 1 of 4We know that s(t) = 12at2 + v0t + s0. In this situation, we have a = ft/s2, v0 = ft/s, and s0 = h, where h is the height of the cliff (in feet) that we wish to find.
A rocket, initially at rest, is fired horizontally with a horizontal acceleration of 12 m/s2. If the rocket is fired from a cliff 80 meters high, what is the distance in meters between the landing location and the bottom of the cliff? (Note: use g=10 m/s2).
When the stone hits the ground, its height is 0 ft. We can now use0 = s(4.75) = −16 2 + h.Solving for h we find that the height of the cliff ish = ft.
6. An object is projected horizontally at a velocity of 40m/s from a cliff 20m high. Calculate: a) The time taken to hit the ground. b) The distance from the foot of the cliff when the object hits the ground.
We have s(t) = 12at2 + v0t + s0 = −16t2 + h. Therefore, the velocity isv(t) = s'(t) = .
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