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6. An object is projected horizontally at a velocity of 40m/s from a cliff 20m high. Calculate: a) The time taken to hit the ground. b) The distance from the foot of the cliff when the object hits the ground.

Question

  1. An object is projected horizontally at a velocity of 40m/s from a cliff 20m high. Calculate: a) The time taken to hit the ground. b) The distance from the foot of the cliff when the object hits the ground.
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Solution

a) The time taken to hit the ground can be calculated using the equation of motion:

t = sqrt(2h/g)

where: h = height from which the object is projected = 20m g = acceleration due to gravity = 9.8m/s²

Substituting the given values into the equation:

t = sqrt(2*20/9.8) = sqrt(40.8163) = 6.39 seconds (approximately)

b) The distance from the foot of the cliff when the object hits the ground can be calculated using the formula:

d = v*t

where: v = velocity of the object = 40m/s t = time taken to hit the ground = 6.39 seconds

Substituting the given values into the equation:

d = 40*6.39 = 255.6 meters (approximately)

So, the object will hit the ground 255.6 meters away from the foot of the cliff.

This problem has been solved

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