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What are the odds against choosing a green or red marble from a bag that contains two blue marbles, one green marble, seven white marbles, and four red marbles?

Question

What are the odds against choosing a green or red marble from a bag that contains two blue marbles, one green marble, seven white marbles, and four red marbles?

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Solution

Sure, let's break it down step by step:

  1. Determine the total number of marbles:

    • Blue marbles: 2
    • Green marbles: 1
    • White marbles: 7
    • Red marbles: 4

    Total number of marbles = 2 + 1 + 7 + 4 = 14

  2. Determine the number of favorable outcomes (choosing a green or red marble):

    • Green marbles: 1
    • Red marbles: 4

    Total favorable outcomes = 1 + 4 = 5

  3. Determine the number of unfavorable outcomes (not choosing a green or red marble):

    • Total marbles: 14
    • Favorable outcomes: 5

    Unfavorable outcomes = Total marbles - Favorable outcomes = 14 - 5 = 9

  4. Calculate the odds against choosing a green or red marble:

    • Odds against = Number of unfavorable outcomes : Number of favorable outcomes = 9 : 5

So, the odds against choosing a green or red marble are 9:5.

This problem has been solved

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