Marsha has a bag that contains 4 green marbles, 8 yellow marbles, and 20 red marbles. If she chooses one marble from the bag, what is the probability that the marble is not red?A.B.C.D.SUBMITarrow_backPREVIOUS
Question
Marsha has a bag that contains 4 green marbles, 8 yellow marbles, and 20 red marbles. If she chooses one marble from the bag, what is the probability that the marble is not red?A.B.C.D.SUBMITarrow_backPREVIOUS
Solution
First, let's find out the total number of marbles in the bag.
Marsha has 4 green marbles, 8 yellow marbles, and 20 red marbles.
So, the total number of marbles is 4 (green) + 8 (yellow) + 20 (red) = 32 marbles.
The question asks for the probability that the marble Marsha chooses is not red. This means we are interested in the green and yellow marbles only.
There are 4 green marbles and 8 yellow marbles, so there are 4 + 8 = 12 marbles that are not red.
The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes.
In this case, the favorable outcomes are choosing a green or yellow marble, and the total outcomes are the total number of marbles.
So, the probability that the marble is not red is 12 (green and yellow marbles) divided by 32 (total marbles), or 12/32.
This can be simplified by dividing both the numerator and the denominator by 4, to get 3/8.
So, the probability that the marble Marsha chooses is not red is 3/8.
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