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Melissa has a bag that contains 6 red marbles, 8 yellow marbles, and 18 blue marbles. If she chooses one marble from the bag, what is the probability that the marble is not blue?A.B.C.D.

Question

Melissa has a bag that contains 6 red marbles, 8 yellow marbles, and 18 blue marbles. If she chooses one marble from the bag, what is the probability that the marble is not blue?A.B.C.D.

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Solution

To solve this problem, we first need to determine the total number of marbles in the bag.

Step 1: Add up all the marbles 6 red marbles + 8 yellow marbles + 18 blue marbles = 32 total marbles

Step 2: Determine the number of outcomes that do not involve choosing a blue marble. This would be the sum of the red and yellow marbles, which is 6 red + 8 yellow = 14 marbles.

Step 3: The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes. In this case, the favorable outcomes are the scenarios where a blue marble is not chosen, and the total outcomes are the total number of marbles.

So, the probability that the marble Melissa chooses is not blue is 14 (red and yellow marbles) divided by 32 (total marbles), or 14/32.

This can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 2, to get 7/16.

So, the probability that the marble is not blue is 7/16.

This problem has been solved

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