derive an expression for work done in stretching a wire
Question
derive an expression for work done in stretching a wire
Solution
Sure, here is the step by step derivation for the work done in stretching a wire:
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Let's consider a wire of length 'L' and area of cross-section 'A'. The wire is made of a material with Young's modulus 'Y'.
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If we apply a force 'F' to stretch the wire, it will extend by a small amount 'dx'.
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The work done 'dW' in stretching the wire by 'dx' is given by the force 'F' times the displacement 'dx'. So, dW = F*dx.
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According to Hooke's law, the force required to stretch the wire is proportional to the extension. So, F = Y*(A/L)*dx.
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Substituting this into the equation for work gives: dW = Y*(A/L)*dx^2.
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To find the total work done in stretching the wire from its original length 'L' to a new length 'L + ΔL', we need to integrate this expression from 'L' to 'L + ΔL'.
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The integral of dx^2 from 'L' to 'L + ΔL' is (1/3)*(ΔL)^3.
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Therefore, the total work done 'W' in stretching the wire is given by: W = (1/3)YA*(ΔL)^3 / L.
This is the expression for the work done in stretching a wire.
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