Knowee
Questions
Features
Study Tools

derive an expression for work done in stretching a wire

Question

derive an expression for work done in stretching a wire

🧐 Not the exact question you are looking for?Go ask a question

Solution

Sure, here is the step by step derivation for the work done in stretching a wire:

  1. Let's consider a wire of length 'L' and area of cross-section 'A'. The wire is made of a material with Young's modulus 'Y'.

  2. If we apply a force 'F' to stretch the wire, it will extend by a small amount 'dx'.

  3. The work done 'dW' in stretching the wire by 'dx' is given by the force 'F' times the displacement 'dx'. So, dW = F*dx.

  4. According to Hooke's law, the force required to stretch the wire is proportional to the extension. So, F = Y*(A/L)*dx.

  5. Substituting this into the equation for work gives: dW = Y*(A/L)*dx^2.

  6. To find the total work done in stretching the wire from its original length 'L' to a new length 'L + ΔL', we need to integrate this expression from 'L' to 'L + ΔL'.

  7. The integral of dx^2 from 'L' to 'L + ΔL' is (1/3)*(ΔL)^3.

  8. Therefore, the total work done 'W' in stretching the wire is given by: W = (1/3)YA*(ΔL)^3 / L.

This is the expression for the work done in stretching a wire.

This problem has been solved

Similar Questions

derivation for elastic potential energy in a stretched wire?

A one metre long steel wire of cross-sectional area of 1 mm2 is  extended by 1 mm. If Y = 2 × 1011 N m-2, then the work done is

What force is required to stretch a steel wire 1 cm2 in cross section to double its length? Young’smodulus of steel is q = 20x1010N / ma.4.0 X 106Nb.40 x 106 Nc. 20 x 106 Nd.None of the above

A copper wire of length 1m is stretched by 1cm then the strain in the wire is

A spring has a natural length of 25 cm and a force of 35N is required to stretch and hold thespring to a length of 32 cm. What is the work required to stretch the spring from length of30 cm to a length of 45 cm?

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.