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What force is required to stretch a steel wire 1 cm2 in cross section to double its length? Young’smodulus of steel is q = 20x1010N / ma.4.0 X 106Nb.40 x 106 Nc. 20 x 106 Nd.None of the above

Question

What force is required to stretch a steel wire 1 cm2 in cross section to double its length? Young’smodulus of steel is q = 20x1010N / ma.4.0 X 106Nb.40 x 106 Nc. 20 x 106 Nd.None of the above

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Solution

The question seems to be incomplete. However, I can guide you on how to solve such a problem if we had all the necessary information.

The formula to calculate the force (F) required to stretch a wire is given by:

F = (Y * A * ΔL) / L

Where: Y = Young's modulus of the material (in this case, steel) A = Cross-sectional area of the wire ΔL = Change in length of the wire L = Original length of the wire

From the question, we know that: Y = 20 x 10^10 N/m^2 (Young's modulus of steel) A = 1 cm^2 = 1 x 10^-4 m^2 (converted from cm^2 to m^2) ΔL = L (since the wire is stretched to double its original length)

Substituting these values into the formula, we get:

F = (20 x 10^10 N/m^2 * 1 x 10^-4 m^2 * L) / L

Simplifying this, we find that the force required is 2 x 10^6 N.

However, without the original length of the wire (L), we cannot calculate the exact force required. Please provide the original length of the wire to get the exact answer.

This problem has been solved

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