A wire of length 3 meters and a cross-sectional area of 0.002 m² experiences a strain of 0.03. If the Young's modulus of the material is 6 x 10^10 N/m², what is the applied force?
Question
A wire of length 3 meters and a cross-sectional area of 0.002 m² experiences a strain of 0.03. If the Young's modulus of the material is 6 x 10^10 N/m², what is the applied force?
Solution
To find the applied force, we can use the formula for stress, which is stress = force/area. But we also know that stress = Young's modulus * strain.
So we can set these two equations equal to each other:
force/area = Young's modulus * strain
We can solve for force by multiplying both sides by area:
force = Young's modulus * strain * area
Now we can plug in the given values:
force = 6 x 10^10 N/m² * 0.03 * 0.002 m²
force = 3.6 x 10^6 N
So the applied force is 3.6 x 10^6 N.
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