A material has a length of 5 meters, a cross-sectional area of 0.003 m², and a Young's modulus of 4 x 10^10 N/m². If it experiences a stress of 2 x 10^7 N/m², what is the strain?
Question
A material has a length of 5 meters, a cross-sectional area of 0.003 m², and a Young's modulus of 4 x 10^10 N/m². If it experiences a stress of 2 x 10^7 N/m², what is the strain?
Solution
The strain on a material can be calculated using the formula:
Strain = Stress / Young's Modulus
Given in the problem, we have:
Stress = 2 x 10^7 N/m² Young's Modulus = 4 x 10^10 N/m²
Substituting these values into the formula, we get:
Strain = (2 x 10^7 N/m²) / (4 x 10^10 N/m²) = 0.0005
So, the strain on the material is 0.0005.
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