A steel wire is stretched, resulting in a strain of 0.02. If the wire has a length of 6 meters and a Young's modulus of 2 x 10^11 N/m², what is the applied force?
Question
A steel wire is stretched, resulting in a strain of 0.02. If the wire has a length of 6 meters and a Young's modulus of 2 x 10^11 N/m², what is the applied force?
Solution
To find the applied force, we can use the formula for stress, which is stress = force/area. However, we don't have the area. But we know that stress = Young's modulus x strain. So we can find the stress first.
Step 1: Calculate Stress Stress = Young's modulus x strain Stress = 2 x 10^11 N/m² x 0.02 Stress = 4 x 10^9 N/m²
Now, we know that stress is also equal to force/area. We can rearrange this formula to solve for force.
Step 2: Calculate Force Force = Stress x Area
But we don't have the area of the wire. If we assume the wire is a cylinder, we would need the radius or diameter of the wire to calculate the area. Without this information, we cannot calculate the force.
Similar Questions
A wire of length 3 meters and a cross-sectional area of 0.002 m² experiences a strain of 0.03. If the Young's modulus of the material is 6 x 10^10 N/m², what is the applied force?
A wire of length 4 meters is stretched by a force of 800 N, resulting in a strain of 0.02. What is the Young's modulus of the material?
If a wire with a cross-sectional area of 0.02 m² experiences a force of 2000 N and stretches by 0.1 meters, what is the Young's modulus of the material?
What force is required to stretch a steel wire 1 cm2 in cross section to double its length? Young’smodulus of steel is q = 20x1010N / ma.4.0 X 106Nb.40 x 106 Nc. 20 x 106 Nd.None of the above
A steel rod with a length of 2 meters and a cross-sectional area of 0.002 m² is stretched by a force of 800 N. What is the strain in the rod?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.