The standard cell potential (E°cell) of a cell is calculated by subtracting the reduction potential of the anode from the reduction potential of the cathode.

In this case, we have two metals Ma and Mb with reduction potentials of -0.19 V and -0.85 V respectively.

We need to identify which metal is the anode (where oxidation occurs) and which is the cathode (where reduction occurs).

In a galvanic/voltaic cell, the metal with the lower reduction potential will be the anode. Here, Mb has a lower reduction potential (-0.85 V) than Ma (-0.19 V), so Mb is the anode and Ma is the cathode.

Now, we can calculate the standard cell potential:

E°cell = E°cathode - E°anode
E°cell = (-0.19 V) - (-0.85 V)
E°cell = 0.66 V

So, the standard cell potential of the cell is +0.66 V.

Question

The standard cell potential (E°cell) of a cell is calculated by subtracting the reduction potential of the anode from the reduction potential of the cathode.

In this case, we have two metals Ma and Mb with reduction potentials of -0.19 V and -0.85 V respectively.

We need to identify which metal is the anode (where oxidation occurs) and which is the cathode (where reduction occurs).

In a galvanic/voltaic cell, the metal with the lower reduction potential will be the anode. Here, Mb has a lower reduction potential (-0.85 V) than Ma (-0.19 V), so Mb is the anode and Ma is the cathode.

Now, we can calculate the standard cell potential:

E°cell = E°cathode - E°anode
E°cell = (-0.19 V) - (-0.85 V)
E°cell = 0.66 V

So, the standard cell potential of the cell is +0.66 V.

Knowee AI · Accepted Answer

The standard cell potential (E°cell) of a cell is calculated by subtracting the reduction potential of the anode from the reduction potential of the cathode.

In this case, we have two metals Ma and Mb with reduction potentials of -0.19 V and -0.85 V respectively.

We need to identify which metal is the anode (where oxidation occurs) and which is the cathode (where reduction occurs).

In a galvanic/voltaic cell, the metal with the lower reduction potential will be the anode. Here, Mb has a lower reduction potential (-0.85 V) than Ma (-0.19 V), so Mb is the anode and Ma is the cathode.

Now, we can calculate the standard cell potential:

E°cell = E°cathode - E°anode
E°cell = (-0.19 V) - (-0.85 V)
E°cell = 0.66 V

So, the standard cell potential of the cell is +0.66 V.

What is the standard cell potential of a cell made of theoretical metals Ma/Ma and Mb/Mb if the reduction potentials are –0.19 V and –0.85 V, respectively?Group of answer choices+1.04 V+0.66 V–1.04 V–0.66 V

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