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What will be the standard cell potential of galvanic cell with the following reaction?2Cr(s)+3Cd2+(aq)→2Cr3+(aq)+3Cd(s)[Given E°Cr3+/Cr=−0.74V and E°Cd2+/Cd=−0.40V]

Question

What will be the standard cell potential of galvanic cell with the following reaction?2Cr(s)+3Cd2+(aq)→2Cr3+(aq)+3Cd(s)[Given E°Cr3+/Cr=−0.74V and E°Cd2+/Cd=−0.40V]

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Solution

To find the standard cell potential (E°cell) for the given reaction, we need to use the Nernst equation:

E°cell = E°cathode - E°anode

First, we need to identify the cathode and anode in the reaction. The cathode is where reduction occurs, and the anode is where oxidation occurs.

In the given reaction, Cr is getting oxidized to Cr3+ and Cd2+ is getting reduced to Cd. So, Cr is the anode and Cd2+ is the cathode.

Given that E°Cr3+/Cr = -0.74V (this is the oxidation, so it's for the anode) and E°Cd2+/Cd = -0.40V (this is the reduction, so it's for the cathode).

Substituting these values into the Nernst equation gives:

E°cell = (-0.40V) - (-0.74V) = 0.34V

So, the standard cell potential of the galvanic cell for the given reaction is 0.34V.

This problem has been solved

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