determine the empirical formula of barium sulfide.

The empirical formula of a compound gives the simplest whole number ratio of atoms of each element in the compound.

1. Identify the symbol of each element: Barium (Ba) and Sulfur (S).

2. Identify the number of atoms of each element in the compound: Barium (1) and Sulfur (1).

3. Write the empirical formula by listing the elements in the same order as in the molecular formula and writing the number of atoms of each element as a subscript: BaS.

So, the empirical formula of barium sulfide is BaS.

Sure, here are the steps to determine the empirical formula of barium sulfide:

1. Identify the symbols of the elements in the compound: Barium (Ba) and Sulfur (S).

2. Write down the atomic masses of these elements: Barium (Ba) has an atomic mass of approximately 137.33 g/mol and Sulfur (S) has an atomic mass of approximately 32.06 g/mol.

3. Determine the ratio of the atoms in the compound: Barium sulfide is composed of one atom of barium and one atom of sulfur, so the ratio is 1:1.

4. Write the empirical formula: Since the ratio of barium to sulfur is 1:1, the empirical formula of barium sulfide is BaS.