What is the empirical formula of a compound containing 40.0% sulfur and 60.0% oxygen by mass?
Question
What is the empirical formula of a compound containing 40.0% sulfur and 60.0% oxygen by mass?
Solution
To find the empirical formula of a compound, follow these steps:
-
Assume you have 100g of the compound. This means you have 40g of sulfur (S) and 60g of oxygen (O).
-
Convert the mass of each element to moles. The atomic mass of S is approximately 32g/mol and that of O is approximately 16g/mol. So, you have 40g/32g/mol = 1.25 mol of S and 60g/16g/mol = 3.75 mol of O.
-
Write the ratio of the moles. This gives you the formula S1.25O3.75.
-
To get the empirical formula, you need to find the simplest whole number ratio. Divide each of the subscripts by the smallest number of moles calculated (in this case, 1.25). This gives you S1O3.
So, the empirical formula of the compound is SO3.
Similar Questions
A compound is found to contain 23.3% magnesium, 30.7% sulfur, and 46.0% oxygen. What is the empirical formula of this compound?
6. A compound is found to have 80% sulfur and 20% oxygen. What is the empirical formula?SO2SO3S2OS2O3
Find the empirical formula of a compound that is 53.7% iron and 46.3% sulfur.What is the empirical mass of the said compound in g/mol?Use:Fe = 56 amuS = 32 amu
What is the empirical formula of a compound that contains 46.3% lithium and 53.7% oxygen?
A compound has 40% Carbon 6.6% Hydrogen & 53.3% Oxygen. Calculate the Empirical Formula of the compound.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.