The bond angle and % of d-character in SFs are

The question seems to be incomplete. The molecule SFs is not a recognized chemical compound. If you meant SF6 (Sulfur Hexafluoride), then the bond angle in SF6 is 90 degrees between the adjacent fluorine atoms and 180 degrees across the opposite fluorine atoms.

As for the % of d-character, in SF6, the sulfur atom is sp3d2 hybridized. The percentage of d-character can be calculated as the number of d orbitals involved in hybridization divided by the total number of orbitals involved in hybridization, multiplied by 100.

In this case, there are 2 d orbitals and a total of 6 orbitals (1 s, 3 p, and 2 d). So, the percentage of d-character is (2/6)*100 = 33.33%.