What is the bond angle in BF3?

To determine the bond angle in BF3, we need to consider the molecular geometry of the molecule. BF3 has a trigonal planar molecular geometry, meaning that the central boron atom is surrounded by three fluorine atoms in a flat, triangular arrangement.

In a trigonal planar geometry, the bond angles between the central atom and the surrounding atoms are all equal. Since BF3 has three fluorine atoms, the bond angles will be the same for each fluorine-boron-fluorine bond.

To calculate the bond angle, we can use the concept of the VSEPR (Valence Shell Electron Pair Repulsion) theory. According to this theory, the electron pairs around the central atom repel each other and try to maximize their distance from each other.

In BF3, there are three bonding pairs of electrons between the boron and fluorine atoms. These bonding pairs repel each other, causing the fluorine atoms to spread out as far as possible. As a result, the bond angle in BF3 is approximately 120 degrees.

Therefore, the bond angle in BF3 is approximately 120 degrees.