To determine the most polar bond among the options (a) C – F, (b) C – O, (c) C – Br, and (d) C – S, we need to consider the electronegativity difference between the atoms involved in each bond.

Electronegativity is a measure of an atom's ability to attract electrons towards itself in a chemical bond. The greater the electronegativity difference between two atoms, the more polar the bond.

Looking at the periodic table, we can see that fluorine (F) has the highest electronegativity value of 3.98, followed by oxygen (O) with a value of 3.44, bromine (Br) with a value of 2.96, and sulfur (S) with a value of 2.58.

Comparing the electronegativity values, we can see that the C – F bond has the highest electronegativity difference (3.98 - 2.55 = 1.43), making it the most polar bond among the options.

Therefore, the correct answer is (a) C – F.

Question

To determine the most polar bond among the options (a) C – F, (b) C – O, (c) C – Br, and (d) C – S, we need to consider the electronegativity difference between the atoms involved in each bond.

Electronegativity is a measure of an atom's ability to attract electrons towards itself in a chemical bond. The greater the electronegativity difference between two atoms, the more polar the bond.

Looking at the periodic table, we can see that fluorine (F) has the highest electronegativity value of 3.98, followed by oxygen (O) with a value of 3.44, bromine (Br) with a value of 2.96, and sulfur (S) with a value of 2.58.

Comparing the electronegativity values, we can see that the C – F bond has the highest electronegativity difference (3.98 - 2.55 = 1.43), making it the most polar bond among the options.

Therefore, the correct answer is (a) C – F.

Knowee AI · Accepted Answer

To determine the most polar bond among the options (a) C – F, (b) C – O, (c) C – Br, and (d) C – S, we need to consider the electronegativity difference between the atoms involved in each bond.

Electronegativity is a measure of an atom's ability to attract electrons towards itself in a chemical bond. The greater the electronegativity difference between two atoms, the more polar the bond.

Looking at the periodic table, we can see that fluorine (F) has the highest electronegativity value of 3.98, followed by oxygen (O) with a value of 3.44, bromine (Br) with a value of 2.96, and sulfur (S) with a value of 2.58.

Comparing the electronegativity values, we can see that the C – F bond has the highest electronegativity difference (3.98 - 2.55 = 1.43), making it the most polar bond among the options.

Therefore, the correct answer is (a) C – F.

The most polar bond is(a) C – F (b) C – O (c) C – Br (d) C – S

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