A number consists of two digits whose sum is 8. If 18 is added to the number its digits are reversed. Find the number
Question
A number consists of two digits whose sum is 8. If 18 is added to the number its digits are reversed. Find the number
Solution
Sure, let's solve this step by step:
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Let's denote the tens digit as "x" and the units digit as "y". According to the problem, the sum of the digits is 8, so we can write this as: x + y = 8.
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The problem also states that if 18 is added to the number, the digits are reversed. This means that the tens digit becomes the units digit and the units digit becomes the tens digit. We can write this as: 10x + y + 18 = 10y + x.
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Now we have a system of two equations that we can solve. Let's simplify the second equation by subtracting x and subtracting 10y from both sides: 9x - 9y = 18.
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We can simplify this further by dividing all terms by 9: x - y = 2.
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Now we have two simple equations: x + y = 8 and x - y = 2. We can solve this system by adding the two equations together: 2x = 10.
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Solving for x gives us x = 5. Substituting x = 5 into the first equation gives us 5 + y = 8, so y = 3.
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Therefore, the original number is 53.
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