Let's denote the tens digit as "x" and the units digit as "y".

From the problem, we know that:

1) x + y = 7 (The sum of the digits of a two digit number is 7)

2) 10y + x = 2*(10x + y) - 2 (If the digits are reversed, the new number decreased by 2, equals twice the original number)

We can simplify the second equation to:

10y + x = 20x + 2y - 2
8y = 19x - 2

Now we have a system of two equations, and we can solve it step by step.

First, let's express y from the first equation:

y = 7 - x

Now we can substitute y in the second equation:

8*(7 - x) = 19x - 2
56 - 8x = 19x - 2
58 = 27x
x = 58 / 27

Since x must be an integer, there is no solution for this system of equations, which means there is no such two-digit number that satisfies the conditions of the problem.

Question

Let's denote the tens digit as "x" and the units digit as "y".

From the problem, we know that:

1) x + y = 7 (The sum of the digits of a two digit number is 7)

2) 10y + x = 2*(10x + y) - 2 (If the digits are reversed, the new number decreased by 2, equals twice the original number)

We can simplify the second equation to:

10y + x = 20x + 2y - 2
8y = 19x - 2

Now we have a system of two equations, and we can solve it step by step.

First, let's express y from the first equation:

y = 7 - x

Now we can substitute y in the second equation:

8*(7 - x) = 19x - 2
56 - 8x = 19x - 2
58 = 27x
x = 58 / 27

Since x must be an integer, there is no solution for this system of equations, which means there is no such two-digit number that satisfies the conditions of the problem.

Knowee AI · Accepted Answer