The number obtained by interchanging the two digits of a two-digit number is less than the original number by 18. The sum of the two digits of the number is 16. What is the original number?
Question
The number obtained by interchanging the two digits of a two-digit number is less than the original number by 18. The sum of the two digits of the number is 16. What is the original number?
Solution
Let's denote the tens digit as "x" and the units digit as "y".
From the problem, we know two things:
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The sum of the digits is 16. So, we can write this as: x + y = 16
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The number obtained by interchanging the digits is less than the original number by 18. This means that the original number (10x + y) is 18 more than the number obtained by interchanging the digits (10y + x). We can write this as: 10x + y = 18 + 10y + x
Solving these two equations will give us the values of x and y, which represent the digits of the original number.
Let's simplify the second equation: 10x + y = 18 + 10y + x --> 9x - 9y = 18 --> x - y = 2
Now we have a system of two equations:
x + y = 16 x - y = 2
Adding these two equations together, we get: 2x = 18, so x = 9.
Substituting x = 9 into the first equation, we get: 9 + y = 16, so y = 7.
Therefore, the original number is 97.
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