Two bodies A (30kg) and B (50kg) tied with a light string are placed on a frictionless table. A force F acting at B pulls this system with an acceleration of 2 ms–2. The tension in the string is:A 60N B 100N C 35N D 140N
Question
Two bodies A (30kg) and B (50kg) tied with a light string are placed on a frictionless table. A force F acting at B pulls this system with an acceleration of 2 ms–2. The tension in the string is:A 60N B 100N C 35N D 140N
Solution
To solve this problem, we need to use Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration (F = ma).
First, let's find the total force acting on the system. The total force is the force F, which is equal to the total mass of the system (the sum of the masses of bodies A and B) times the acceleration.
F = (m_A + m_B) * a F = (30kg + 50kg) * 2 m/s² F = 80kg * 2 m/s² F = 160N
Now, let's find the force acting on body A, which is equal to its mass times the acceleration. This force is also the tension in the string.
T = m_A * a T = 30kg * 2 m/s² T = 60N
So, the tension in the string is 60N, which corresponds to option A.
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