A 0.22 kg ball is going in circles at a frequency of 25 Hz due to being attached to a 1.2 m long string. What is the tension in the string?*1 point3125.0 N6515.6 N6615.6 N6815.6 NWhat is the force of gravity experienced by an objec
Question
A 0.22 kg ball is going in circles at a frequency of 25 Hz due to being attached to a 1.2 m long string. What is the tension in the string?*1 point3125.0 N6515.6 N6615.6 N6815.6 NWhat is the force of gravity experienced by an objec
Solution
The question seems to be cut off. However, I can help you with the first part of the question.
The tension in the string can be found using the formula for centripetal force, which is F = mω²r, where m is the mass of the object, ω is the angular velocity, and r is the radius of the circle.
First, we need to convert the frequency to angular velocity. The relationship between frequency (f) and angular velocity (ω) is ω = 2πf. So, ω = 2π * 25 Hz = 157.08 rad/s.
Then we can substitute the values into the formula:
F = mω²r F = 0.22 kg * (157.08 rad/s)² * 1.2 m F = 6615.6 N
So, the tension in the string is 6615.6 N.
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