Three block are connected as shown, on a horizontal frictionless table and pulled to the right with a force T3 = 60 N. If m1 = 10 kg, m2 = 20 kg and m3 = 30 kg, the tension T2 is- 10 N20 N30 N60 N
Question
Three block are connected as shown, on a horizontal frictionless table and pulled to the right with a force T3 = 60 N. If m1 = 10 kg, m2 = 20 kg and m3 = 30 kg, the tension T2 is- 10 N20 N30 N60 N
Solution
To solve this problem, we need to use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
First, we calculate the total mass of the system (m1 + m2 + m3) which is 10 kg + 20 kg + 30 kg = 60 kg.
Next, we calculate the acceleration of the system using the formula F = ma, where F is the total force and m is the total mass. The total force is given as T3 = 60 N. So, the acceleration (a) = F/m = 60 N / 60 kg = 1 m/s².
Now, we can calculate the tension T2. T2 is the force that accelerates m1 and m2. So, T2 = (m1 + m2) * a = (10 kg + 20 kg) * 1 m/s² = 30 N.
So, the tension T2 is 30 N.
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