The position of a model train, in feet along a railroad track, is given bys(t) = 2.5t + 19after t seconds.(a) How fast is the train moving? ft/sec(b) Where is the train after 4 seconds? feet along the track(c) When will the train be 34 feet along the track?t = sec

A train that is moving at 25 m/s slows down at a rate of 3 m/s^2 in 4 seconds. How far does it travel while braking?

A train on a straight stretch of track starts from rest and accelerates at a steady 2 m/s/s. Determine its speed after 1 second, 2 seconds, and 5 seconds.

The correct answer is:  The train takes 3 seconds to pass the signal post. See the diagram below that shows the motion of the train.  The star shows the front (engine) of the train.The time of passing starts from time T2T 2​ and lasts till time T3T 3​ . Let this time be = T3T 3​ - T2T 2​ = T seconds.Then the distance moved by the engine (star on the train) during the passing time is = 20 m/s ×× T seconds = 20T metersBut from the diagram it is clear that this distance is the length of the train = 60 meters. So:  20 ×× T =  60  ⇒⇒  T = 3 seconds.

The train gets up to 8 m/s along the same straight track. The driver applies the brakes causing the train to accelerate at –0.5 m/s/s.Determine its speed after 1 second, 2 seconds, and 5 seconds.

When my friend, Prof. Rajesh Sadagopan was travelling to Bangalore, he found that his train, which was moving uniformly, passed a telegraph post in 14 seconds and a platform 210 m long in 42 seconds.  Find the length of the train.