A compound contains 54.26% C, 5.32% H, 14.89% N and the rest is O. How many atoms of N are present in the empirical formula of the compound?Group of answer choices5476
Question
A compound contains 54.26% C, 5.32% H, 14.89% N and the rest is O. How many atoms of N are present in the empirical formula of the compound?Group of answer choices5476
Solution
To find the number of atoms of N in the empirical formula, we first need to convert the percentages into grams (assuming we have 100g of the compound, so the % becomes g). Then, we convert the grams into moles.
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Convert the percentage of N into grams. If the compound is 100g, then N would be 14.89g because it's 14.89% of the compound.
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Convert the grams of N into moles. The atomic mass of N is approximately 14.01g/mol. So, 14.89g divided by 14.01g/mol equals approximately 1.06 moles of N.
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The empirical formula is the simplest, most reduced ratio of elements in a compound. As such, we compare the amount of moles of each element to each other. In this case, we only need the amount of N, which is 1.06 moles.
So, there is 1 atom of N in the empirical formula of the compound.
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