The empirical formula of an organic compound is C 3 H4 N. Its molecular weight is 108.Find the amount of carbon in one mole of the compound. Show all the steps involved.(Atomic weights: C- 12; H- 1; N- 14)

First, let's find the molecular weight of the empirical formula, C3H4N.

The atomic weight of Carbon (C) is 12, Hydrogen (H) is 1, and Nitrogen (N) is 14.

So, the molecular weight of the empirical formula is (312) + (41) + (1*14) = 36 + 4 + 14 = 54 g/mol.

Given that the molecular weight of the compound is 108 g/mol, we can see that the molecular formula is twice the empirical formula. So, the molecular formula of the compound is C6H8N2.

Now, let's find the amount of carbon in one mole of the compound.

In the molecular formula, there are 6 moles of Carbon. Since the atomic weight of Carbon is 12, the weight of Carbon in one mole of the compound is 6 * 12 = 72 g.

So, the amount of carbon in one mole of the compound is 72 g.