An organic compound containing C and H gave the following analysis C = 40%, H = 6.7%. Its empirical formulawould be
Question
An organic compound containing C and H gave the following analysis C = 40%, H = 6.7%. Its empirical formulawould be
Solution
The empirical formula of a compound is the simplest whole number ratio of atoms of each element in a compound.
Here's how to find the empirical formula for this compound:
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Assume that you have 100g of the compound. This means that you have 40g of Carbon (C) and 6.7g of Hydrogen (H).
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Convert the mass of each element to moles. The atomic mass of C is approximately 12g/mol and the atomic mass of H is approximately 1g/mol. So, you have 40g/12g/mol = 3.33 mol of C and 6.7g/1g/mol = 6.7 mol of H.
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Write the ratio of moles. This gives you C3.33H6.7.
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Divide each number of moles by the smallest number of moles calculated. In this case, 3.33 is the smallest. So, you get C(3.33/3.33)H(6.7/3.33) = CH2.
So, the empirical formula of the compound is CH2.
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