Sure, I can help with that. The distance between two points in a 2D plane can be calculated using the distance formula derived from Pythagoras' theorem. The distance d between two points (x1, y1) and (x2, y2) is given by:

d = sqrt[(x2-x1)² + (y2-y1)²]

Let's apply this formula to your problem:

(i) For the points (2, 3) and (4, 1), we have:

x1 = 2, y1 = 3, x2 = 4, y2 = 1

So, the distance d is:

d = sqrt[(4-2)² + (1-3)²]
d = sqrt[(2)² + (-2)²]
d = sqrt[4 + 4]
d = sqrt[8]
d = 2*sqrt[2]

So, the distance between the points (2, 3) and (4, 1) is 2*sqrt[2] units.

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Sure, I can help with that. The distance between two points in a 2D plane can be calculated using the distance formula derived from Pythagoras' theorem. The distance d between two points (x1, y1) and (x2, y2) is given by:

d = sqrt[(x2-x1)² + (y2-y1)²]

Let's apply this formula to your problem:

(i) For the points (2, 3) and (4, 1), we have:

x1 = 2, y1 = 3, x2 = 4, y2 = 1

So, the distance d is:

d = sqrt[(4-2)² + (1-3)²]
d = sqrt[(2)² + (-2)²]
d = sqrt[4 + 4]
d = sqrt[8]
d = 2*sqrt[2]

So, the distance between the points (2, 3) and (4, 1) is 2*sqrt[2] units.

Knowee AI · Accepted Answer

Sure, I can help with that. The distance between two points in a 2D plane can be calculated using the distance formula derived from Pythagoras' theorem. The distance d between two points (x1, y1) and (x2, y2) is given by:

d = sqrt[(x2-x1)² + (y2-y1)²]

Let's apply this formula to your problem:

(i) For the points (2, 3) and (4, 1), we have:

x1 = 2, y1 = 3, x2 = 4, y2 = 1

So, the distance d is:

d = sqrt[(4-2)² + (1-3)²]
d = sqrt[(2)² + (-2)²]
d = sqrt[4 + 4]
d = sqrt[8]
d = 2*sqrt[2]

So, the distance between the points (2, 3) and (4, 1) is 2*sqrt[2] units.

Find the distance between the following pairs of points: (i) (2, 3), (4, 1) 10th class statistcis

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